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Leona [35]
3 years ago
9

Which number is the same distance from 0 on a number line as 3/2 answers -3 -3/2 -2/3 2/3 3

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer: -3/2

Step-by-step explanation:

To find its distance away from 0, then just find its opposite.

On the number line if you graph 3/2,  its opposite will be -3/2

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There is a bag with only red marbles and blue marbles. The probability of randomly choosing a red marble is 2 9 . There are 63 m
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The main idea is the number of marbles and the denominator of the probability. All you have to do is multiply the fraction by a fraction which is equal to 1 which makes the denominator equal to 63. We know 63 is a multiple of 9. 9 goes 7 times in 63 so we multiple the fraction \frac{2}{9} with \frac{7}{7} which gives, \frac{2 * 7}{9 * 7} which when evaluated gives \frac{14}{63} and the numerator is the number of red marbles in the bag. So there are 14 red marbles in the bag :D

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What is the remainder when (x^3 1) is divided by (x^2 – x 1)?<br> x 1<br> x<br> 2<br> 0
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Hello,
x^3+1=(x+1)(x^2-x+1)\\&#10;Remainder\ is \ 0\\\\&#10;&#10;

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3 years ago
I’ll CashApp someone 5$ if they can kindly answer this, I’ve been stuck on this and it’s due tonight, I will even mark you Brain
lisov135 [29]

Answer: Part A is 2 and 6 Part B is 2

Step-by-step explanation:

Part A: Here is the explanation. So, you started at with the expression 3x^2+8x+4 and when you're are factoring, you have 3x^2+px+pq+4. You can substitute the p and q for 6 and 2. What they did is they replaced 8x with px+qx. To get 8x, p needs to be 6 and q needs to be 2, or the other way around. TIP: The numbers just have to add up to 8 on this one. It doesn't have to be 6 and 2.

Part B: Here is what I got so far... 3x(x+r) is 3x^2+3xr. Also, s(x+r) is sx+sr. The equation becomes, 3x^2+3xr+sx+sr. R can be 2 and s can be 2. Here is my reasoning: The original expression was 3x^2+8x+4. We already have the 3x^2, so now we need to find what the others are by determining what r and s equal. R and s can both be 2 to make four. 2x2 is 4. Let's see if it can make 8.  3xr becomes 6x and sx becomes 2x. 6x+2x is 8x.

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Point d is on line segment ce. Given ce = 18 and cd=12,determine the length de
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Answer:

Step-by-step explanation:

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2 years ago
Solve the initial-value problem<br><br> y' = x^4 - \frac{1}{x}y, y(1) = 1.
natta225 [31]

The ODE is linear:

y'=x^4-\dfrac yx

y'+\dfrac yx=x^4

Multiplying both sides by x gives

xy'+y=x^5

Notice that the left side can be condensed as the derivative of a product:

(xy)'=x^5

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Since y(1)=1,

1=\dfrac16+C\implies C=\dfrac56

so that

\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}

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3 years ago
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