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Kobotan [32]
2 years ago
14

Algebra TA UL 2019-2020

Mathematics
1 answer:
True [87]2 years ago
4 0
If the slope is 5 so is the x’s number

ax+b=y

a=5 because of the slope

5x+b=y
Put the points 2 instead of x and -3 instead of y

10+b=-3

b is -13


so the answer is 5x-13=y
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Match each equation with a solution from the list of values.
vova2212 [387]

Answer:

1. a=2.3

2. b=2.6

3. c=2.3

4.d=2.6

5. e=40

6. f=1/6

7. g=85

Step-by-step explanation:

4 0
3 years ago
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Which is greater -5 or -7
Natasha_Volkova [10]
-5 I believe so idk...
5 0
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What is the mode of these numbers?<br> 10, 12, 8, 11, 10, 15, 7
lana66690 [7]

Answer:

The mode is 10

Step-by-step explanation:

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zubka84 [21]

Answer:

slope = x=4

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Step-by-step explanation:

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A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height
melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

Time cannot be a negative value, so

x\geq 0

The height of the food packet cannot be a negative value, so

f(x)\geq 0

We need to replace -15x^2+6000 for f(x) in the above inequality to find the domain.

-15x^2+6000\geq 0 \; \;  [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0

The possible solutions of the above inequality are given by the intervals (-\infty , -2], [-2,2], [2,\infty ). We need to pick test point from each possible solution interval and check whether that test point make the inequality (x+200)(x-200)\leq 0 true. Only the test point from the solution interval [-200, 200] make the inequality true.

The values of x which will make the above inequality TRUE is -200\leq x\leq 200

But we already know x should be positive, because time cannot be negative.

Conclusion:

Domain of the given function is 0\leq x\leq 200

4 0
3 years ago
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