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FromTheMoon [43]
3 years ago
14

4y − 3x − 2y 11 x − 2 x

Mathematics
1 answer:
Inessa05 [86]3 years ago
4 0
By rearranging it:
-3x-2x-22xy+4y
=-5x-22xy+4y answer
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Which graph represents all of the solutions of 3n–15≤ -3?
swat32

Answer:

B.

Step-by-step explanation:

5 0
3 years ago
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How many different ways can four team members from the group of fifteen be lined up for a photograph?
damaskus [11]

Answer:

32760

Step-by-step explanation:

This is a permutation of 15 objects taken 4 at a time.  To calculate this, we use the formula:

_nP_r=\frac{n!}{(n-r)!}

In our case, n is 15 and r is 4:

_{15}P_4=\frac{15!}{(15-4)!}=\frac{15!}{11!}=32760

6 0
3 years ago
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1. Write an equation in slope-intercept form for a line passing through (-3,3) with a slope of 1.
PIT_PIT [208]

1)


\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=1[x-(-3)] \\\\\\ y-3=1(x+3)\implies y-3=x+3\implies y=x+6


2)


\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-2}{1-(-4)}\implies \cfrac{10}{1+4}\implies \cfrac{10}{5}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=2[x-(-4)]\implies y-2=2(x+4) \\\\\\ y-2=2x+8\implies y=2x+10

8 0
3 years ago
Find the volume. Round to the nearest tenth.<br> 20m<br> 5 m<br> 18 m
Thepotemich [5.8K]
The answer is 1800 because you have to follow the formula for volume which is
Volume=Length x Width x Height
1800= 18m x 5m x 20m
5 0
3 years ago
Substitution. (6 points) <br> 3x + 2y = 11 <br> y = 5x - 1<br><br> {show work}
nexus9112 [7]
3x+2y=11
y=5x-1

Substitute the y in the first equation:
3x+2(5x-1)=11
y=5x-1

3x+10x-2=11
y=5x-1

13x=13
y=5x-1

Now substitute the x to find the y:
x=1
y=5-1=4
8 0
3 years ago
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