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Vesna [10]
3 years ago
5

Find the area of a rectangle with length (2x + 3) and width (x - 4). A) 2x2 - 11x - 12 B) 2x2 - 5x + 12 C) 2x2 + 11x + 12 D) 2x2

- 5x - 12
Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

D

area of a rectangle = length × width

area = (2x + 3)(x - 4) ( expand using FOIL )

       = 2x² - 8x + 3x - 12 = 2x² - 5x - 12 → D


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Step-by-step explanation:  We are given to find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -5i.

We know that

if x = a is a zero of a real polynomial function p(x), then (x - a) is a factor of the polynomial p(x).

So, according to the given information, (x - 2) and ( x + 5i) are the factors of the given polynomial.

Also, we know that complex zeroes occur in conjugate pairs, so 5i will also be a zero of the given polynomial.

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Hi there, Welcome to Brainly :)

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