Answer:
A + B = 24
16A + 20B = 434
Step-by-step explanation:
To write a system of equations for this scenario, let's say that A represents the number of hours machine A ran, and B represents the number of hours machine B ran.
The first equation will be:
A + B = 24
because the total number of hours ran is 24.
The second equation will be:
16A + 20B = 434
because the total number of items made is 434.
A + B = 24
16A + 20B = 434
First solve for one variable, and let's just do A.
Using the first equation, A + B = 24, A is equal to 24 - B.
Substitute this value to the second equation.
16 (24 - B) + 20B = 434
384 - 16B + 20B = 434
4B = 50
B = 12.5
Now use this value of B to find the value of A.
A + 12.5 = 24
A = 11.5
Machine A ran for 11.5 hours, and Machine B ran for 12 hours.
Answer: Option C. Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Solution:
Conditional relative frequency single employees in grade 2:
[(Single employees in job grade 2)/(Total employees in job grade 2)]*100%=
(222/4,239)*100%=0.052370842*100%=5.2370842% approximately 5.2%
Conditional relative frequency married employees in grade 2:
[(Married employees in job grade 2)/(Total employees in job grade 2)]*100%=
(3,927/4,239)*100%=0.926397735*100%=92.6397735% approximately 92.6%
92.6%>5.2%:
Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Ummm let me see so what u have to do is
