Answer:
Step-by-step explanation:
So, we have-
(6 x .1) + (3 x .01) + (2 x .001)
So, we will solve inside of the parenthesis first.
6 x .1 = <u>.6</u>
So, we got that settled next-
3 x .01 = <u>.03</u>
We got that settled last-
2 x .001 = <u>.002</u>
Lastly, we add them all.
.6 + .03 + .002 = .632
Now we compare.
.632 > .629
So, there is your answer!
Hope this helps!
Answer:
Goodluck my dude.
Step-by-step explanation:
Answer:
kdkidn ir ejido la la la ayudara a las dos ángulos congruentes y q
Why are you even asking, i'll edit the answer once I know.
Answer:
D) q + d = 330
0.25q + 0.1d = 6
Step-by-step explanation:
Let q= numbers of quarters
d = number of dimes
q + d = 33 ...........(1)
q = 33 - d
xq + yd = 6 ..........(2)
We will consider the options to know the correct answer
From option A
q +d = 6
25q + 10d = 33
This is wrong
Option B
q + d = 60
0.25q + 0.1d = 33
This is also wrong
Option C
q+d = 33
25q + 10d = 6
Put q = 33 -d in equation 2
25(33 - d) + 10q = 6
825 - 25d + 10d = 6
825 - 15d = 6
-15d = 6-825
-15d = -819
d = -819/-15
d= 54.6
This is also wrong because d exceeds the combination.
Option D
q+d = 33
0.25q + 0.1d = 6
Put q = 33 -d in equation 2
0.25(33 - d) + 0.1d = 6
8.25 - 0.25d + 0.1d = 6
8.25 - 0.15d = 6
-0.15d = 6 - 8.25
-0.15d = -2.25
d = -2.25/ -0.15
d = 15
q = 33 - 15
q = 18
This is correct
