Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards
the distance between them is 476 miles, and they met 8.5hrs later
let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs
we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2
thus
solve for "r", to see how fast the cyclist was going
what about the car? well, the car's rate is r + 33.2
Answer:
B.) 83.7758
Step-by-step explanation:
-66 is the 27th term.
You have a function in terms of n. Recall that n is the nth term in the sequence.
Substitute n = 27 into the equation to find the 27th term.
a₂₇ = -10 + (27 + 1)(-2) = -10 + (28)(-2) = -10 - 56 = -66
3d+8=2d-17
-2d -2d
__________
d+8=-17
-8 -8
__________
d=-25
Answer:
2 hours 32 minutes
Step-by-step explanation:
Subtract.
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