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rewona [7]
3 years ago
9

The surface area of a prism is 125 in2. the 2 is suposed to be cubed or squared or whatever

Mathematics
1 answer:
Rasek [7]3 years ago
6 0
Surface area is area so it's in^2 or inches squared
12 in=1 foot therfor
1in<1 foot
so therfor if we converted the surface area to feet, then the number would decrease, but the actual area would stay the same because we just converted the units, we didn't change the actuall area

therfor the answers are A and E
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Simplify an expression for the perimeter of the rectangle shown.
Zanzabum

The perimeter of the rectangle is P = (17.2x₊16.4).

Given that,

Length, l = 8.6x₊3

Width, b = 5.2

In the formula P=2l+2w, where l is the rectangle's length and w is its width, the perimeter P of a rectangle is determined. Using the formula A=l×w, where l is the length and w is the width, we can determine the area A of a rectangle.

We need to find the expression for the perimeter of the rectangle. The formula for the perimeter of the rectangle is given by :

P=2(l₊b)

Putting values of l and b in the above formula:

p = 2(8.6x ₊ 3 ₊ 5.2)

= 2(8.6x ₊ 8.2)

= 2(8.6x) ₊ 2(8.2)

= 17.2x ₊ 16.4

So, the required perimeter of the rectangle is 17.2x₊16.4.

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1 year ago
The conjugate of (2+i)²/3+i, in the form of a+ib, is
goblinko [34]

Given that

(2+i)²/(3+i)

On multiplying both numerator and the denominator with (3-i) then

⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]

⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]

⇛ [(2+i)²(3-i)]/[(3²-i²)

⇛ [(2+i)²(3-i)]/(9-i²)

⇛ [(2+i)²(3-i)]/[9-(-1)]

Since ,i² = -1

⇛ [(2+i)²(3-i)]/(9+1)

⇛ [(2+i)²(3-i)]/10

⇛ [{2²+i²+2(2)(i)}(3-i)]/10

⇛ (4+i²+4i)(3-i)/10

⇛ (4-1+4i)(3-i)/10

⇛ (3+4i)(3-i)/10

⇛ (9-3i+12i-4i²)/10

⇛ (9+9i-4(-1))/10

Since, i² = -1

⇛(9+9i+4)/10

⇛(13+9i)/10

⇛ (13/10)+ i (9/10)

We know that

The conjugate of a+ib is a-ib

So,

The conjugate of (13/10)+ i (9/10) is

(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)

<u>Answer:-</u>The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)

<em>Additional</em><em> comment</em><em>:</em>

  • The conjugate of a+ib is a-ib and
  • i = -1
  • (a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².
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2 years ago
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37.76 is the answer....
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3 years ago
A function f defined by f(x) = x² + px + q is such that f(3) = 6 and f¹(3) = 0. Find the value of q.
CaHeK987 [17]

Answer:

q = 15

Step-by-step explanation:

Given

f(x) = x² + px + q , then

f(3) = 3² + 3p + q = 6 , that is

9 + 3p + q = 6 ( subtract 9 from both sides )

3p + q = - 3 → (1)

---------------------------------------

f'(x) = 2x + p , then

f'(3) = 2(3) + p = 0, that is

6 + p = 0 ( subtract 6 from both sides )

p = - 6

Substitute p = - 6 into (1)

3(- 6) + q = - 3

- 18 + q = - 3 ( add 18 to both sides )

q = 15

5 0
3 years ago
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