Please provide the context of problem
The perimeter of the rectangle is P = (17.2x₊16.4).
Given that,
Length, l = 8.6x₊3
Width, b = 5.2
In the formula P=2l+2w, where l is the rectangle's length and w is its width, the perimeter P of a rectangle is determined. Using the formula A=l×w, where l is the length and w is the width, we can determine the area A of a rectangle.
We need to find the expression for the perimeter of the rectangle. The formula for the perimeter of the rectangle is given by :
P=2(l₊b)
Putting values of l and b in the above formula:
p = 2(8.6x ₊ 3 ₊ 5.2)
= 2(8.6x ₊ 8.2)
= 2(8.6x) ₊ 2(8.2)
= 17.2x ₊ 16.4
So, the required perimeter of the rectangle is 17.2x₊16.4.
Learn more about Area Perimeter here:
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Given that
(2+i)²/(3+i)
On multiplying both numerator and the denominator with (3-i) then
⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]
⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]
⇛ [(2+i)²(3-i)]/[(3²-i²)
⇛ [(2+i)²(3-i)]/(9-i²)
⇛ [(2+i)²(3-i)]/[9-(-1)]
Since ,i² = -1
⇛ [(2+i)²(3-i)]/(9+1)
⇛ [(2+i)²(3-i)]/10
⇛ [{2²+i²+2(2)(i)}(3-i)]/10
⇛ (4+i²+4i)(3-i)/10
⇛ (4-1+4i)(3-i)/10
⇛ (3+4i)(3-i)/10
⇛ (9-3i+12i-4i²)/10
⇛ (9+9i-4(-1))/10
Since, i² = -1
⇛(9+9i+4)/10
⇛(13+9i)/10
⇛ (13/10)+ i (9/10)
We know that
The conjugate of a+ib is a-ib
So,
The conjugate of (13/10)+ i (9/10) is
(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)
<u>Answer:-</u>The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)
<em>Additional</em><em> comment</em><em>:</em>
- The conjugate of a+ib is a-ib and
- i = -1
- (a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².
Answer:
q = 15
Step-by-step explanation:
Given
f(x) = x² + px + q , then
f(3) = 3² + 3p + q = 6 , that is
9 + 3p + q = 6 ( subtract 9 from both sides )
3p + q = - 3 → (1)
---------------------------------------
f'(x) = 2x + p , then
f'(3) = 2(3) + p = 0, that is
6 + p = 0 ( subtract 6 from both sides )
p = - 6
Substitute p = - 6 into (1)
3(- 6) + q = - 3
- 18 + q = - 3 ( add 18 to both sides )
q = 15
