Given that p(x) is a polynomial in 2 and a € R. If (x – a) is a factor of p(I), then p(a) must be
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(We know this from a=1/9 and r=3)
Simplifying this, we get:
Since we're finding the first term that exceeds 1000, let's set it equal to 1000.
Multiplying both sides by 27
n≈9.2
We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,
=2187
Therefore the first term that exceeds 1000 is 2187, and it is the 10th term