Given that <span>the number of possible handshakes within a group of n people is given by the equation:

</span> $N= \frac{1}{2} (n^2-n)$
<span>
Given that there are 105 people at a party, the number of possible handshakes is given by:

</span> $N= \frac{1}{2} (105^2-105) \\ \\ = \frac{1}{2} (11025-105)=10920$ <span>
</span>

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2 years ago

How to plot (3,-3) on a graph?

netineya [11]

They y-axis represents the -3 now all that you need to do is line it up to -3 and 3 in the graph

7 0

2 years ago

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. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m

Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available