Answer:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
Step-by-step explanation:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
We are given 3 equations. Using these equations we can find f(h(2)).
h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9
f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74
so f(h(2))=74
Answer:
- first shift: 13,750 bulbs
- second shift: 2500 bulbs
Step-by-step explanation:
The production ratio is ...
shift 1 : shift 2 = 5.5 : 1 = 11 : 2
so, the production on shift 1 as a ratio to the total is ...
shift 1 : total = 11 : (11+2) = 11 : 13
The first shift produced ...
(11/13)(16,250 bulbs) = 13,750 bulbs . . . . first shift
and the second shift produced ...
(2/13)(16,250 bulbs) = 2,500 bulbs . . . . second shift
_____
Of course, once you have one of the numbers, you can also find the other by using the 5.5 factor or by subtracting from total production.