The distance from his home to his work place is 118.125 miles
<h3>How to find the distance from his home to his work place?</h3>
He drove from home to work at an average speed of 45 mph. Therefore,
speed = 45 mph
let
time = x
speed = distance / time
distance = 45x
His return trip home took 45 minutes longer because he could only drive at 35 mph. Therefore,
45 minutes = 0.75 hours
distance = 35(x + 0.75)
distance = 35x + 26.25
Therefore,
45x = 35x + 26.25
45x - 35x = 26.25
10x = 26.25
x = 26.25 / 10
x = 2.625
Therefore,
distance = 45(2.625) = 118.125 miles
learn more on distance here: brainly.com/question/21329221
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Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
Hi,

Now just divide both sides of equation by -4.

Simplify:

Decimal form:

Hope this helps.
r3t40