Question

What are some of the ways tan θ= sinθ/cosθ can be expressed?

Answer 1

Answer:

We know that

$sinx=\frac{1}{cosecx}$

$cosx=\frac{1}{secx}$

Given $tanx=\frac{sinx}{cosx}$

$tanx=\frac{1}{cosecx\times cosx}$

$tanx=\frac{sinx \times secx }{1}$

$tanx=\frac{secx}{cosecx}$

$tan x= \frac{1}{cotx}$