4 years ago

The class can contain at most 28 students.

Mathematics

1 answer:

Eddi Din [679]4 years ago

8 0

28

Bcdfghhfghhfd

28 :)

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Find a degree 3 polynomial having zeros -5, 1 and 5 and the coefficient of x^3 equal 1

mote1985 [20]

Answer:

$x^3 -x^2 -25x +25$

Step-by-step explanation:

$\text{The roots are,}~ \alpha = -5,~ \beta = 1 ~ \text{and}~ \gamma = 5\\\\\text{The polynomial is,}\\\\~~~x^3 - (\alpha + \beta + \gamma)x^2+(\alpha \beta + \beta \gamma+ \gamma \alpha)x - \alpha\beta \gamma\\\\=x^3 - (-5+1+5)x^2 +(-5 \cdot 1 + 1 \cdot 5 + 5 \cdot -5)x - (-5)(1)(5)\\\\=x^3 -(0+1)x^2 + (-5+5-25)x +25\\\\=x^3 -x^2 -25x +25$