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2 years ago

3. The product of two even numbers is always divisible by 4. a) True b) false

Mathematics

2 answers:

lisov135 [29]2 years ago

8 0

Answer: True

Here's an example:

6 x 8 = 48

48/ 4 = 12

14 x 12 = 168

168/4 = 42

son4ous [18]2 years ago

8 0

The answer is definitely true

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Sam is keeping track of the distances at a long jump competition. The jumper from East side High jumped 7.85 meters. The jumper

nataly862011 [7]

The answer is A)Eastside High

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3 years ago

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The prime number which is also even is<br> a) 0<br> b) -2<br> c) 2<br> d) 6

Archy [21]

Answer:

c) 2

Step-by-step explanation:

a prime number is a number which is only completely divisible by 1 and itself

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2 years ago

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Subject Algebra 1

Mashutka [201]

Answer:

$10x^{2}-34$

Step-by-step explanation:

Because we are told equivalent expressions for y and z we can plug those in to 2(y+z).

$2((3x^{2}+x^{2}-5)+(x^{2}-12))$

Then simplify by combining like terms of the expressions. Values ending in x^2 can be combined with each other.

$2(5x^{2}-17)$

Now we can distribute the 2 by multiplying each value in the parentheses by 2.

$10x^{2}-34$

6 0

2 years ago

A bag contain 3 black balls and 2 white balls.

Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

$Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\$

$Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}$

Probability of at least one black( means BB or BW or WB)

$=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}$

Probability of at most one black ( means WW or WB or BW)

$=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}$

a) Probability both black without replacement

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

b) Probability of one black and one white

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

c) Probability of at least one black ( BB or BW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}$

d) Probability of at most one black ( BW or WW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}$

6 0

2 years ago

WOULD A KIND S0UL PLEASE HELP ME OUT???!!!!!!!!!!!!

Akimi4 [234]

Answer:

here you go mate. sorry I just calculated straight away since you needed it urgently.

but if you use the (x+10, y-6) you'll arrive at similar answers as mine

5 0

2 years ago

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