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pshichka [43]
3 years ago
5

Who does a retail company sell products to?

Mathematics
1 answer:
Oxana [17]3 years ago
7 0
Retail is<span> the process of </span>selling<span> consumer goods or services to customers through multiple channels of distribution to earn a profit. 

End Consumers</span>
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What is the probability of getting the multiples of 3 when a number is chosen at random from whole numbers less than 20
irakobra [83]
Hold up I’m gonna help u
8 0
3 years ago
Help~~~~~~~~~~~~~~~~~~~~~~~~~
igor_vitrenko [27]

Answer:

28.25 square units

Step-by-step explanation:

A circumference of the circle is

C=2\pi r,

where r is the radius of the circle.

So,

18.84=2\pi r\\ \\r=\dfrac{18.84}{2\pi}=\dfrac{9.42}{\pi}\ cm

The area of the circle is

A=\pi r^2

Substitute the value of the radius:

A=\pi \cdot \left(\dfrac{9.42}{\pi}\right)^2=\dfrac{9.42^2}{\pi}\approx 28.25\ un^2

8 0
3 years ago
Read 2 more answers
a school has 415 third grade and 338 second graders how many more third graders are there than second graders?
Alika [10]

Answer:

There are 77 more third graders than there are second graders.

Step-by-step explanation:

You just have to subtract 338 from 415 to get your answer.

6 0
3 years ago
Read 2 more answers
Can someone explain this or help me plss .
Ilya [14]

Answer:I'll explain this to you, It's a chart with lined down margin math equation.

Step-by-step explanation:

So the first up/down line margin is X*X, the second is X numbers, third is x^x numbers, fourth is explain the left to right's math solutions into words. Just imply your following numbers into X's and onto your chart. Hopefully this helps.

7 0
3 years ago
Read 2 more answers
Two of the exterior angles of a triangle are $158^\circ$ and $99^\circ.$ Find the third exterior angle, in degrees.
Lisa [10]

Answer:

The third exterior angle is 103^o

Step-by-step explanation:

Given

\theta = 158^o

\alpha = 99^o

Required

The third exterior angle (\beta)

The exterior angles of a triangle add up to 360 degrees.

So:

\theta + \alpha + \beta = 360^o

Make \beta the subject

\beta = 360^o - (\theta + \alpha)

Substitute known values

\beta = 360^o - (158^o + 99^o)

\beta = 103^o

4 0
3 years ago
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