The bacteria was not killed off. In those three days symptoms had stop because the bacteria was dormant. They must have been activated because Jim provided a suitable environment for their growth
Answer:
a. purple allele (C) = 0.609, pink allele (c) = 0.391
b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476
Explanation:
Given -
Purple flowers - 847
Pink flowers - 153
The frequency of recessive genotype i.e

Frequency of recessive allele i.e q is equal to

As per hardy Weinberg's first equilibrium equation -

Frequency of purple homozygous species

Number of purple homozygous species 
Number of pink homozygous species 
Heterozygous species is equal to
