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valkas [14]
3 years ago
14

The cost y in dollars of car rental is related to the number to the number of miles driven x and is approximated by the linear e

quation y=0.25x+5 use the graph go estimate to the nearest whole dollar the cost of the car rental if the number of miles driven is 27
$8
$28.25
$12
$17
Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

$12

Step-by-step explanation:

Currently, we are solving for the cost (y).

Since we are solving for cost (y), we need to plug in our value for the number of miles driven (x). This value is given at the end of the question as we are told that the miles driven is 27. We can plug this into the equation we are given.

y = 0.25(x) + 5

y = 0.25(27) + 5

We multiply 0.25 and 27 to start off with, to get 6.75.

y = 6.75 + 5

Add.

y = 11.75

Since we are told to round up, we round up 11.75 to the nearest dollar.

y = 12

Our final answer is $12.

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Answer:

65.5

Step-by-step explanation:

(74 + 57)divided by 2 = 65.5

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Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim
sergejj [24]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958      

c) p_v =P(t_{34}>2.958)=0.0028    

d) If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

The sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=17 represent the sample mean    

s=4 represent the sample standard deviation

n=35 sample size  

\mu_o =15 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

Since we don't  know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958  

Part c P-value  

The degrees of freedom are given by:

df = n-1= 35-1=34

Since is a right tailed test the p value would be:  

p_v =P(t_{34}>2.958)=0.0028  

Part d Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

7 0
3 years ago
8 5/6 + 2 3/4 +__=14 this is fractions so the answer should be a fraction please help
Mariulka [41]

Answer:

2 5/12

Step-by-step explanation:

8 5/6 + 2 3/4 = 8 10/12 + 2 9/12  =  10 19/12  =  10 + 1 7/12  =  11 7/12

13 12/12 - 11 7/12 = 2 5/12

3 0
3 years ago
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