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3 years ago

What are the solutions to |4b−5|=19

Mathematics

1 answer:

damaskus [11]3 years ago

3 0

B can either equal 6 or -3.5

So, 6 and -3.5 are solutions.

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Surface area of a cylinder with a radius of 7cm and a height of 12

Keith_Richards [23]

Answer:

CSA = 2 * pi * r * h

Step-by-step explanation:

CSA = 2 * 22 * 7 * 12 / 7

= 2 * 22 * 12

528 cm ^3

7 0

3 years ago

Read 2 more answers

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0

3 years ago

Given triangle, ABC is congruent to triangle EDC find A

arlik [135]

Answer:

m<A = 30 degrees.

Step-by-step explanation:

m < C in triangle ABC = m < C in EDC so

x + 13 + 42 + x + 13 = 180

2x = 180 - 13 - 13 - 42

2x = 112

x = 56.

So m < C = 56+13 = 69.

m < B = m < D = 81

M < A = 180 - 69 - 81

= 180 - 150 = 30.

7 0

2 years ago

To get an A in a course, you must have an average of at least 90% on four tests worth 100 points each. Your scores so far are 85

kondaur [170]

Answer:

A score of 117 is needed, which Is not possible since the test is over 100.

Step-by-step explanation:

The other 3 scores are 85, 94,84 . Let's x be the 4th score he must score.

Therefore ( 85 + 94 + 84 + X)/4 =95

Then 263+X /4 =95

Cross mutiplying 4*95=263+X

Therefore X= 380-263

X= 117 which is not possible since the test score is over 100.

6 0

3 years ago

Write an equation to match each statement. Then solve. #1) 8 less than a number x is -12. #2) 15 more than a number k is 2. #3)

guajiro [1.7K]

#1) x-8= -12
#2) 15+k= 2
#3) x/-7= -20
#4) (5/8)(x)= -20

The / in #2 means to divide and the ( ) mean to multiply

5 0

3 years ago