Am I correct????????

lisabon 2012 [21]

37 is a prime number

6 0

3 years ago

Each side of a sandbox is 7 feet long. It will cost $1.00 per square foot to replace the sand in the sandbox. What would be the

arlik [135]

Answer: $7.00

Step-by-step explanation:

each foot is $1, so times 7 is 7 dollars.

3 0

3 years ago

Read 2 more answers

How many solutions does the system of equations have?

Vlad1618 [11]

Answer:

one solution at x=1,y=4 point

4 0

2 years ago

Read 2 more answers

Diana is painting statues.She has 7/8 of a gallon remaining.Each statue requires 1/16 of a gallon of paint. How many statues can

Irina-Kira [14]

The answer for the problem is 7/2

3 0

3 years ago

An automobile manufacturer has given its van a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Fynjy0 [20]

Answer:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

Step-by-step explanation:

Information given

$\bar X=31.1$ represent the sample mean

$\sigma=1.3$ represent the population standard deviation

$n=140$ sample size

$\mu_o =31.3$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:

Null hypothesis: $\mu =31.3$

Alternative hypothesis: $\mu \neq 31.3$

Since we know the population deviation, the statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

4 0

3 years ago