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3 years ago

A vehicular travels a distance of 5t^4-10t^2+6 miles in t+2 minutes

1 answer:

7 0

The complete question is
<span>A vehicle travels a distance of 5t^4-10t^2+6 miles in t+2 minutes how fast is the vehicles speed

we know that
speed=distance/time
distance=</span>5t^4-10t^2+6 miles
time=t+2 minutes
so
You have to divide the distance by the time
speed=[5t^4-10t^2+6]/[t+2] miles/minute

the answer is
the speed is [5t^4-10t^2+6]/[t+2] miles/minute

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3 years ago

Find the value of c so that the polynomial p(×) is divisible by (x-4). p(×)=cx^3-15x-68

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Answer:

Step-by-step explanation:

x-4=0

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3 years ago

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3 years ago

Divide. Write your answer as a fraction or mixed number in simplest form. -4/5 divided by 16/15

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3 years ago

Read 2 more answers

Need help pls<br>thank you in advance

ira [324]

Answer:

<u />

$\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}$

$\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10$

$\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10$

<h3><u>Standard Deviation</u></h3>

$\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}$

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

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2 years ago