Answer:
Using the log combination rules to reduce the famous Sakur-Tetrode equation, The change in entropy is given as:
∆S = NK*ln(V"V$/V").
Where V"V$ is final Volume (Vf) after constraint's removal,
V" is Initial Volume (Vi) before constraint's removal.
Temperature (T) is constant, Internal Energy, U is constant, N and K have their usual notations
Explanation:
Given in the question, the container is an adiabatic container.
For an adiabatic contain, it does not permit heat to the environment due to its stiff walls. This implies that the Internal Energy, U is kept constant(Q = U). The temperature is also constant (Isothermal). Thus, the famous Sakur-Tetrode equation will reduce to ∆S = NK* In(Vf/Vi).
Vf is the volume after the constraint is removed(Vf = V"V$). Vi is the volume occupied before the constraint is removed (Vi = V")
Answer:
a. v' = 24.22 x 10 ⁻³
b. β = 0.825 T
Explanation:
V = 150 V , E = 6.0 x 10 ⁶ N / C
a.
¹/₂ * m * v² = e * V
v = √ 2 * e / m * V
v = √ 2 * 1.76 x 10 ¹¹ * 150 v = √ 5.28 x 10 ¹³
v = 7.26 x 10 ⁶ m /s
v' / c = 7.26 x 10 ⁶ m /s / 3.0 x 10 ⁸ = 24.22 x 10 ⁻³
b.
β = E / V
β = 6.0 x 10 ⁶ / 7.266 x 10 ⁶
β = 0.825 T
c.
When the increasing the accelerating potential speed it doesn't change the up wired the electric force and the magnetic force the electron be beat down more .
<u>Answer:</u>
<em>Sand in a beach is warmer than the water of the sea.
</em>
<u>Explanation:</u>
<em>Water absorbs less heat from the sun</em> when compared with sand. Sand is darker and also is less reflective. Because of its darker nature, absorption of heat from the sun will be more. Due to its less reflective nature the sand wouldn’t be able to<em> reflect off the sunlight.
</em>
But water is highly reflective and can reflect off a <em>major portion of the sunlight falling on the sea</em>. The sea is also deep and thus the heat spreads through a large volume unlike in the <em>case of sand.</em> Water also has the nature of constant movement unlike sand which is stable.
<em>This factor also heats up sand more than water.
</em>