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emmasim [6.3K]
3 years ago
14

Heat energy is a form of _____ energy.

Physics
2 answers:
love history [14]3 years ago
5 0
Heat energy is a form of kinetic energy
Anettt [7]3 years ago
4 0
C. Kinetic is the answer you need. like Nanny Mcphee.
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In this section of a circuit, a current of 2.5 A flows across R2. Find the current that flows across R3. Let R1= 3.0 ohm, R2= 8.
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A machine lifts a 35 kg object doing 6860 J worth of work. How much power is produced by the machine if it lifts the object in 4
timofeeve [1]

Answer:

Explanation:

We need the power equation for this which is

P = Work/time

We have everything we need to solve this (the mass of the object is extra information):

P = 6860/4

P = 1715W

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What is the physical energy that stimulates sight?
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Particle moves in a circle of radius 90m with a constant speed 25m/s. how many revolution does it make in 30sec​
Serggg [28]

Answer:

<em>n =1.33 revolutions</em>

Explanation:

<u>Uniform Circular Motion</u>

The angular speed can be calculated in two different ways:

\displaystyle \omega=\frac{v}{r}

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\omega=2\pi f

Where:

f = frequency

Solving for f:

\displaystyle f=\frac{\omega}{2\pi}

Since the frequency is calculated when the number of revolutions n and the time t are known:

\displaystyle f=\frac{n}{t}

We can solve for n:

n=f.t

The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:

\displaystyle \omega=\frac{25}{90}

\displaystyle \omega=0.278\ rad/s

Now we calculate f:

\displaystyle f=\frac{0.278}{2\pi}

f=0.04421\ Hz

Calculating the number of revolutions:

n = 0.04421*30

n =1.33 revolutions

8 0
3 years ago
An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magni
SashulF [63]

Answer:

v=10^5\ m/s

Explanation:

Given that,

Magnetic force acting on an electron, F=12.8\times 10^{-19}\ N

The magnitude of the magnetic field,B=8\times 10^{-5}\ T

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

F=qvB

Where

v is the velocity

So,

v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s

So, the magnitude of velocity is10^5\ m/s.

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3 years ago
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