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Helga [31]
4 years ago
5

20. Which statement is false? Rewrite it so that it is true. a. Fusion involves the combination of two smaller atoms into a larg

er atom. b. Fission involves the splitting of an atom into smaller atoms. c. Fission and fusion are two processes that release very little amounts of energy.
Physics
1 answer:
Annette [7]4 years ago
3 0

Answer:

c. Fission and fusion are two processes that release very little amounts of energy.

Explanation:

This statement is false. In fact, both fission and fusion are processes which release very large amounts of energy. The statement can be rewritten as it is true as follows:

"Fission and fusion are two processes that release very large amounts of energy."

Fission occurs when a large nucleus break apart, splitting into smaller nuclei, while fusion occurs when two light nuclei combine together into a larger nucleus. In both cases, the mass of the reactants is larger than the mass of the final products, so some of the mass has been converted into energy, according to Einstein's equation:

E = \Delta m c^2

where

E is the energy released

\Delta m is the mass lost in the process

c is the speed of light

Since c is a very large number (c=3\cdot 10^8 m/s), we see that even a very small mass \Delta m causes the released of a huge amount of energy, so both fission and fusion release large amounts of energy.

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We cannot see a new moon in our sky because __________. aA. A new moon is quite near the Sun in the sky B. it is above the horiz
MariettaO [177]

Answer:

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A beaker of water rests on an electronic balance that reads 875.0 g. A 2.75-cm-diameter solid copper ball attached to a string i
Firdavs [7]

Answer:

a  

The tension in the string is  T = 0.85 N

 b

 The new balance reading is  M_b  =  885.86 g

Explanation:

From the question we are told that

    The mass of the beaker of water is  m = 875 .0g

     The diameter of the copper ball is  d = 2.75 cm = \frac{2.75}{100} = 0.0275 m

There are two forces acting on the copper ball

   The first is the Buoyant force of the water pushing it up which is mathematically represented as

                     F = \rho V g

Where \rho is the density of water which has value of  \rho = 1000 kg/m^3

            g is the acceleration due to gravity g= 9.8 \  m/s^2

          V is the volume of water displaced by the copper ball  which is mathematically evaluated as

                             V = \frac{4}{3}  \pi r^3

The radius r is  r = \frac{d}{3}  = \frac{0.0275}{2} = 0.01375 m

Substituting value  

                        V = \frac{4}{3} * 3.142 * (0.01375)^3

                            V = 1.08 9 *10^{-5 } m^3  

   Substituting for  F

              F = 1000 * 1.089 *10^{-5} * 9.8

               F = 0.1067 N      

     The second force is the weight of the copper ball which is mathematically represented as

       W_c = mg

Now m is the mass which can be mathematically evaluated as

        m =  \rho_c * V

Where  is the density of copper with  value of  \rho_c = 8960 kg /m^3

So      m = 8960 * 1.089 *10^{-5}

         m = 0.0976

So the weight of copper is  

             W_c = 0.09756  *  9.8

            W_c = 0.956 N

Now the tension the string would be mathematically evaluated as

            T = W_c - F

So        T = 0.956 - 0.1067

           T = 0.85 N

From this value we that the string is holding only 0.85 N of the copper weight thus (0.956 - 0.85 = 0.1065 N ) is being held by the balance

Now the mass equivalent of this weight is mathematically evaluated as

             m_z = \frac{1.0645 }{9.8 }

             m_z = 0.01086 kg

Converting to grams  

                     m_z = 10.86 g

So the new balance reading is  

                  M_b  =  875.0 +10.86

                  M_b  =  885.86 g

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