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2 years ago

The satellite that has given us the most precise measurements of the characteristics of the cosmic background radiation is:

Physics

1 answer:

REY [17]2 years ago

8 0

Answer:

An image of the cosmic microwave background radiation, taken by the European Space Agency (ESA)'s Planck satellite in 2013, shows the small variations across the sky (Image credit: ESA/Planck Collaboration) The cosmic microwave background (CMB) is thought to be leftover radiation from the Big Bang, or the time when the universe began

Explanation:

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Identical objects, Object X and Object Y, are tied together by a string and placed at rest on an incline, as shown in the figure

goblinko [34]

The slope of the velocity time graph of an object moving with constant acceleration is constant

It will take approximately 3 seconds for the center of mass of Object X to reach point J near the bottom of the incline

The reason why the above time value is correct is given as follows:

Known parameters:

Initial velocity of the objects, u = 0

The graph in the question is a straight line graph with data points

(0, 0), (0.5, 1.0), (1.0, 2), (3.0, 6), and (3.5, 7)

Given that the slope of the velocity-time graph is constant, we have that the acceleration is constant and is given as follows;

$a = \dfrac{\Delta v}{\Delta t } = \dfrac{v_2 - v_1}{t_2 - t_1}$

Therefore;

$a = \dfrac{6 - 2}{3.0 - 1.0} = 2$

The acceleration, a ≈ 2 m/s²

The distance from the center of mass of the Object X to the point J near the bottom = 9 m

The equation for distance travelled is given as follows;

$s = u\cdot t + \dfrac{1}{2} \cdot a \cdot t^2$

Which gives;

$9 = 0\times t + \dfrac{1}{2} \times 2 \times t^2 = t^2$

t = √9 = 3

The time it will take the center of mass of Object X to reach point J near the bottom of the incline is t = 3 seconds

Learn more about motion under constant acceleration here:

brainly.com/question/16391598

6 0

3 years ago

A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.

Gekata [30.6K]

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] = $6.5*10^{4}\ m/s$

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity $[\theta]$ = 15 degree.

We are asked to calculate the magnetic force experienced by the charged particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force $\vec F=q(\ \vec V \times \vec B)$

i.e F = $=qVBsin\theta$

$=6.8*6.5*10^{4}*1.4*sin15$

$=61.88*10^{4}sin15$

$=61.88*10^4*0.2588\ N$

$=16.016*10^4\ N$

$=1.6*10^5\ N$

Hence, the force experienced by the charged particle is C i.e $1.6*10^5 N$

4 0

3 years ago

Read 2 more answers

A helium balloon has a pressure of 40 psi at 20°C. What will the pressure be at 40°C? Assume constant volume and mass.

Likurg_2 [28]

Answer:

P V = N R T ideal gas equation

P2 / P1 = T2 / T1 where the other variables are constant

P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi

5 0

2 years ago

The current in a hair dryer measures 15 amps the resistance of the hair dryer is 8 ohms

suter [353]

The voltage at the input to the hair dryer is

V = (current) · (resistance)

V = (15 A) · (8 Ω)

V = 120 volts

__________________________________

The power dissipated by the hair dryer is

P = (current)²· (resistance)

P = (15 A)² · (8 Ω)

P = 1800 watts

3 0

3 years ago

Consider a metal single crystal oriented such that the normal to the slip plane and the slip directions are at angles of 43.1° a

Bond [772]

Answer:

resolve shear stress = 22 MPa

Explanation:

Given data

slip plane α = 43.1°

slip directions β = 47.9°

shear stress = 20.7 MPa (3,000 psi)

applied stress =45 mPa (6,500 psi)

to find out

what stress will be necessary

solution

we know that

resolve shear stress = aplied stress × cosα × cosβ

resolve shear stress = 45 × cos(43.1) × cos(47.9)

resolve shear stress = 22 MPa

we can say that here single cristal will be yield

because resolve shear stress is bigger than critical shear stress

3 0

4 years ago