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4 years ago

How do you solve -2 -(-5)= when using subtracting integers

2 answers:

4 0

the answer is 7. To subtract integers, rewrite as adding opposites and use the rules for addition of integers. Recall that rules for addition of integers is: Rule 1: The sum of two or more positive integers is a positive integer. The sum of two or more negative integers is a negative integer.

Svetach [21]4 years ago

3 0

it is -10 because -2x-5=10 and you have a - left over so it is -10

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Fred solved the equation 8(3x – 7) = -6(x + 7) + 4 as shown.

OleMash [197]

Answer: He added 4 to a negative 42 and said it was 46 but its supposed to simplify to -38. X=3/5

3 0

3 years ago

Find the volume of a cone with a height of 7yd and a base diameter of 6yd . use the value 3.14 for π , and do not do any roundin

____ [38]

I think the volume of the cone is 65.94yd because the radius is 3 and the height is 7 also 3 to the second power equals 9 then 3.14 multiplied by 9 equals 28.26 and finally 28.26 multiplied by 7/3 equals 65.94

V=3.14 x r^2 h/3
V=3.14 x 3^2 7/3

6 0

3 years ago

PLEASE HELP ASAP!!!

Brut [27]

Answer:

The other angle would also measure 89°.

3 0

3 years ago

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t),

pishuonlain [190]

Answer:

S(3)=22

Step-by-step explanation:

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).

$\dfrac{dS}{dt}=k(30-S(t))\\ \dfrac{dS}{dt}+kS(t)=30k\\$The integrating factor: e^{\int k dt}=e^{kt}\\$Multiply all through by the integrating factor\\ \dfrac{dS}{dt}e^{kt}+kS(t)e^{kt}=30ke^{kt}$

$(Se^{kt})'=30ke^{kt} dt\\$Integrate both sides\\ Se^{kt}=\dfrac{30ke^{kt}}{k}+C$ (C a constant of integration)\\Se^{kt}=30e^{kt}+C\\$Divide both sides by e^{kt}\\S(t)=30+Ce^{-kt}$

When t=0, S(t)=15

$15=30+Ce^{-k*0}\\C=15-30\\C=-15$

When t = 2, S(t)=20

$20=30-15e^{-2k}\\20-30=-15e^{-2k}\\-10=-15e^{-2k}\\e^{-2k}=\dfrac23\\$Take the natural log of both sides$\\-2k=\ln \dfrac23\\k=-\dfrac{\ln(2/3)}{2}$

Therefore:

$S(t)=30-15e^{\frac{\ln(2/3)}{2}t}\\$When t=3$\\S(t)=30-15e^{\frac{\ln(2/3)}{2} \times 3}\\S(3)=21.8 \approx 22$

8 0

3 years ago

Divide 50 by half and add 20 and <br> multiply by 2

aivan3 [116]

The value of the expression will be equal to 145.

<h3>What is an expression?</h3>

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that make an expression for divide 50 by half and add 20 and multiply by 2.

The expression will be solved as below,

E = 50/2 + 25 x 2 + 50 + 20

Solve the above expression by PEMDAS,

E = 25 + 50 + 70

E = 145

To know more about an expression follow

brainly.com/question/25968875

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8 0

1 year ago

Read 2 more answers