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agasfer [191]
4 years ago
8

How do you solve -2 -(-5)= when using subtracting integers

Mathematics
2 answers:
alisha [4.7K]4 years ago
4 0

the answer is 7. To subtract integers, rewrite as adding opposites and use the rules for addition of integers. Recall that rules for addition of integers is: Rule 1: The sum of two or more positive integers is a positive integer. The sum of two or more negative integers is a negative integer.

Svetach [21]4 years ago
3 0

it is -10 because -2x-5=10 and you have a - left over so it is -10

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Answer:

1)   x=\dfrac12

2)   n = -3 \ \ \textsf{and} \ \ m = -4

3)  see below

4)  A:  0 = 1

Step-by-step explanation:

<u>Question 1</u>

15-0.5(4x-2)+4x=17

\implies 15-2x+1+4x=17

\implies 2x+16=17

\implies 2x=1

\implies x=\dfrac12

<u>Question 2</u>

\textsf{rearrange} \ n=m+1 :

\implies -m=-n+1

\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\

\implies0=n+3

\implies n=-3

\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:

\implies m=-3-1

\implies m=-4

<u>Question 3</u>

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

<u>Question 4</u>

3j=k

k=3j+1

\textsf{rearrange} \ 3j=k :

\implies -k=-3j

\textsf{add equations}\  -k=-3j \ \ \textsf{and}\ \ k=3j+1:

\implies 0=1

Solution = A

6 0
3 years ago
(08.01 LC)
Luba_88 [7]

Answer:

(2, 0)

There is one solution

Step-by-step explanation:

Given the set of equations

x+y = 2

2x+y = 4

Substract both equations

x - 2x = 2 - 4

-x = -2

Multiply thrugh by -1

-1(-x) = -1(-2)

x = 2

Substitute x = 2 into equation1 ;

From 1, x+y = 2

2 + y = 2

y = 2-2

y = 0

hence the solution to the system of equation is (2, 0). Hence there is only one solution

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3 years ago
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Answer:

Step-by-step explanation:

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3 years ago
Evaluate each expression.<br> 6! =<br> 3! - 2!= 1
Lady_Fox [76]

Answer:

6!=720

3! • 2!=12

Step-by-step explanation:

We must recall that the factorial of a number n (positive or zero) is the product of all the integers from n down to 1

n!= n(n-1)(n-2)...1

Let's evaluate the given expressions

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Similarly

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Finally

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3 years ago
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