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Anestetic [448]
3 years ago
6

Does this set of ordered pairs represent a function? Why or why not? -1,5), (0, -3), (2, 7), (4,0), (7, 5)) A. No, because two o

f the y-values are the same. OB. Yes, because there are two xvalues that are the same. OC. Yes, because every xvalue corresponds to exactly one yvalue D. No, because one xvalue corresponds to two different values. ​

Mathematics
1 answer:
alekssr [168]3 years ago
4 0

Answer:

C.

Step-by-step explanation:

All the x-values are different and go to one y-value.

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F(x)=-8x+20;5-2[f(-1)]<br>​
Anni [7]

Answer:

Step-by-step explanation:

f(x) = -8x + 20

f(-1) = -8* -1 + 20 = 8+20 =28

5 -  2[f(-1)] = 5 - 2*28 = 5 - 56 = -51

8 0
3 years ago
What is the (x,y) ordered pair?
Lesechka [4]
-7x+y=23
6x+7y=-4

y=7x+23
6x+7(7x+23)=-4
6x+49x+161=-4
55x+161-161=-4-161
55x/55=-165/55
x=-3

-7(-3)+y=23
21+y-21=23-21
y=2
5 0
4 years ago
Prove that 5^7+5^6 is divisible by 6.
pishuonlain [190]

Answer:

The Proof for 5^{7}+5^{6}\ is\ divisible\ by\ 6 is below.

Step-by-step explanation:

To Prove:

5^{7}+5^{6}\ is\ divisible\ by\ 6

Proof:

We know law of indices

a^{m}.a^{n}=a^{m+n}

Therefore,

Step 1: Applying law of indices

\dfrac{5^{7}+5^{6}}{6}=\dfrac{5^{6}.5^{1}+5^{6}}{6}

Step 2: Taking common 5^{6} we get

\dfrac{5^{7}+5^{6}}{6}=5^{6}\times (\dfrac{5^{1}+1}{6})

Step 3: 5^{1} = 5 so add 5 + 1 we get

\dfrac{5^{7}+5^{6}}{6}=5^{6}\times \dfrac{6}{6}

Step 4: Cancel 6 from both denominator and numerator we get

\dfrac{5^{7}+5^{6}}{6}=5^{6}\times 1=5^{6} ...That is Divisible by 6 Proved

7 0
3 years ago
&lt;
mash [69]

Answer:

2

Step-by-step explanation:

10-2=8.

4 0
3 years ago
Read 2 more answers
Square of 1186.30/1000-1
HACTEHA [7]
1186.30/999=1.187
1.187*1.187=1.409
5 0
4 years ago
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