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dem82 [27]
3 years ago
12

An automobile firm wants to purchase either machine A or machine B. The intial cost of machines A and B are $40,000 and $50,000,

respectively. The power consumption per year of machines A and B are 120 MWh and 100 MWh, respectively. The power cost is $40/MWh. The estimated life of both machines is 10 ye $20,000 for machine B. According to the life-cycle costing approach, the overall cost of machines A and B are:
A. $88,000 and $98,000, respectively
B. 875,000 and $70,000, respectively
C. $118,000 and $110,000, respectively
D. $74,800 and $79,000, respectively
E. $110,000 and $120,000, respectively.
Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:

C. $118,000 and $110,000, respectively.

Step-by-step explanation:

Please consider the complete question.

An automobile firm wants to purchase either machine A or machine B. The intial cost of machines A and B are $40,000 and $50,000, respectively. The power consumption per year of machines A and B are 120 MWh and 100 MWh, respectively. The power cost is $40/MWh. The estimated operating and maintenance cost over 10 years is $30,000 for machine A and $20,000 for machine B.

First of all, we will find the amount spent on power consumption for 10 years by each machine as:

\text{Machine A}=10\cdot 120(\$40)\\\text{Machine A}=\$48,000

\text{Machine B}=10\cdot \$100(\$40)\\\text{Machine A}=\$40,000

Now, we will find overall cost of machines A and B by adding initial cost, power consumption for 10 years and maintenance cost as:

\text{Overall cost of machine A}=\$40,000+\$48,000+\$30,000

\text{Overall cost of machine A}=\$118,000

\text{Overall cost of machine B}=\$50,000+\$40,000+\$20,000

\text{Overall cost of machine B}=\$110,000

Therefore, the overall cost of machines A and B are $118,000 and $110,000, respectively and option C is the correct choice.

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Andreas93 [3]

Answer:

7.5 short tons

Step-by-step explanation:

16 3/10 - 8 4/5 = 7.5

7 0
3 years ago
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At noise pollution cellular,plan A is $30.00 per month and $5.00 for every gigabyte of data . Plan B is $50.00 per month and $2.
Romashka-Z-Leto [24]
Let x be the number of gigabyte of data used.

Plan A:
Total cost = 30 + 5x

Plan B:
Total cost = 50 + 2x

Irfan will use between 5 to 8 gb of data per month.

When x = 5
Plan A = 30 + 5(5) = $55
When x = 8,
Plan A = 30 + 5(8) = $70

When x =5,
Plan B = 50 + 2(5) = $60
When x = 8,
Plan B = 50 + 2(8) = $68

He is probably better off using Plan A. Plan A is a cheaper option up to 7gb of data. He should only swap to Plan B if he consistently use 8gb or more data per month.

8 0
3 years ago
This a comprehension questins​
nikdorinn [45]

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3 0
3 years ago
ZN
solmaris [256]

Given tangent, ZN, to the circle and the arc \widehat{ZMB} = 280°, we have that

the angle formed by the chord BZ and the tangent ZN, ∠BZN is 50°

<h3>Which method can be used to find ∠BZN?</h3>

The given parameters are;

A tangent to the circle O = ZN

m \widehat{ZMB}} = \mathbf{280^{\circ}}

Required:

Angle ∠BZN

Solution;

Please find attached the drawing of the circle and tangent

From the drawing, we have;

∠BOZ = 360° - 280° = 80°

ΔBOZ is an isosceles triangle, which gives;

∠BZO = ∠ZBO

\angle BZO = \dfrac{(180^{\circ}- 80^{\circ}) }{2} = \mathbf{50^{\circ}}

∠OZN = 90° (by definition of a tangent)

∠OZN = ∠BZO + ∠BZN

∠BZN = ∠OZN - ∠BZO

Which gives;

∠BZN = 90° - 40° = 50°

  • The measure of angle ∠BZN =<u> 50°</u>

Learn more about tangents to a circle here:

brainly.com/question/14561226

4 0
2 years ago
Last Sunday a certain store sold copies of Newspaper A for $1 and Newspaper B for 1.25. If r percent of the stores revenue came
Oksanka [162]

Answer:

Option 400p/500-p

Step-by-step explanation:

Let the number of newspaper A sold be 'x'

and the number of newspaper A sold be 'y'

Therefore,

Total revenue = $1x + $1.25y

Total newspapers sold = x + y

Therefore,

according to the question

r = \frac{x}{x + 1.25y}\times100 ..........(1)

and,

p =  \frac{x}{x + y}\times100

or

(x + y)p = 100x

or

y = \frac{x}{p}\times100-x

or

y = \frac{x(100-p)}{p}

substituting y in 1

r = \frac{x}{x + 1.25(\frac{x(100-p)}{p})}\times100

or

r = \frac{100p}{p+125-1.25p}

or

r = \frac{100p}{125-0.25p}

multiply and divide the RHS with 4

we get

r = (400p)÷(500-p)

hence,

Option 400p/500-p

3 0
3 years ago
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