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labwork [276]
3 years ago
6

A bakery sells 12 cupcakes for $10. A Super Market sells 10 cupcakes for $8. Which store is cheaper per cupcake? *

Mathematics
2 answers:
Fantom [35]3 years ago
8 0

Answer:

Step-by-step explanation:

hope this help

Licemer1 [7]3 years ago
8 0

Answer: the super market is cheaper

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Evaluating Algebraic Expression
Olegator [25]

So therefore the answer is –42

Step-by-step explanation:

5*–7–7= –42

7 0
3 years ago
Help me find the value of X
RideAnS [48]

Answer:

B.  x =  53 degrees.

Step-by-step explanation:

The external angles of all polygons add up to 360 degrees, so:

x +  120 + 90+ 97 = 360

x = 360 - 90 - 120 - 97

x =  53 degrees.

8 0
3 years ago
Consider the continuous random variable x, which has a uniform distribution over the interval from 110 to 150. The probability t
Virty [35]

Answer:

The probability that x will take on a value between 120 and 125 is 0.14145

Step-by-step explanation:

For uniform distribution between a & b

Mean, xbar = (a + b)/2

Standard deviation, σ = √((b-a)²/12)

For 110 and 150,

Mean, xbar = (150 + 110)/2 = 130

Standard deviation, σ = √((150-110)²/12 = 11.55

To find the probability that x will take on a value between 120 and 125

We need to standardize 120 & 125

z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87

z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43

P(120 < x < 125) = P(-0.87 < x < -0.43)

We'll use data from the normal probability table for these probabilities

P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145

Hope this Helps!!!

3 0
3 years ago
The sum of four consecutive even integer numbers is 84. find the four numbers.
vodomira [7]

84/4=21

 now take the 2 even numbers below 21 and the 2 even numbers above 21

18 +20 + 22 +24 = 84

 the numbers are 18, 20, 22 & 24

3 0
2 years ago
What is the common factors of 12 and 42 also 63 and 84
kaheart [24]
12|2 \\ 6 \ |2 \\ 3 \ |3 \\ 1 \\\\12=2^2*3 \\\\ 42|2\\21|3\\7\ |7\\1 \\\\42=2*3*7 \\\\ G.C.F(12;42)=2*3=6 \\\\\\\ 63|3 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 63=3^2*7 \\\\ 84|2 \\ 42|2 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 84=2^2*3*7 \\\\ G.C.F(63;84)=3*7=21
3 0
3 years ago
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