All categories

3 years ago

A pair of shoes costs $25 to make. This means that you need to charge a price of at least ___ just to cover your cost.

Mathematics

2 answers:

marin [14]3 years ago

8 0

Answer: $25

Step-by-step explanation: you are not trying to make a profit. You are just trying to cover your cost and they cost $25 to make.

enyata [817]3 years ago

4 0

I believe the answer is $50.

You might be interested in

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

A=1/2 h(x+y) make x the subject

insens350 [35]

Answer:

Step-by-step explanation:

A =1/2 *h (x+y)

A =hx+hy/2

A*2 =hx+hy

2A =hx+hy

2A - hy = hx

(2A -hy)/h = x

6 0

3 years ago

Read 2 more answers

7.2 is 250% of what number

Vlada [557]

Answer:

its 18

Step-by-step explanation:

i took this testtttttttttttt

8 0

2 years ago

Read 2 more answers

The volume of a pyramid varies jointly as the height and the area of the base. If a pyramid has the measurements V=1144

Naddika [18.5K]

Answer:

11040 m³
k ≈ 0.33
V = (1/3)Bh

Step-by-step explanation:

The given relation is ...

V = kBh . . . . . for some base area B, height h, and constant of variation k

We are given length and width of the base so we presume it is a rectangle.

B = l·w = 8·11 = 88 . . . . square meters

The given volume tells us the value of k:

1144 = k(88)(39) . . . . . . cubic meters

1144/3432 = k = 1/3 ≈ 0.33

The value of k is about 0.33.

Then the volume of the larger pyramid is ...

V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³

The general relationship is ...

V = 1/3Bh

7 0

3 years ago

What is the equivalent mixed number to 23/4

lora16 [44]

5 3/4
5 remainder 3
Is the mixed number

4 0

3 years ago

Read 2 more answers