It’s the 2nd answer to the right
We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
Answer:
AB = 25 units
Step-by-step explanation:
In right triangle ACB, 
Therefore, by geometric mean property:
AB = AD + DB
AB = 20 + 5
AB = 25 units
7 is the GCF of 21 and 49. Does this help at all?
Answer:
Step-by-step explanation:
3 
- 2 
- 
First change the two mixed numbers to improper fractions. Multiply the whole number by the denominator then add the numerator to the answer.
Bring the fractions to the same denominator by finding the lowest common multiple of both denominators
Then the answer becomes .
HOPE THIS HELPED
