4 years ago

(4, 3) is a solution to the following system of equations: True or false

Mathematics

2 answers:

Degger [83]4 years ago

4 0

True. X= 4 and Y= 3.

2(4) + 3 = 11

Vlad1618 [11]4 years ago

3 0

Answer:

True

Step-by-step explanation:

2(4)+(3)=11

8+3=11

11=11

(3)=(4)-1

3=4-1

3=3

all you have to do is substitute 4 for you x-values, and substitute 3 for your y-values, and then solve the equations.

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4 years ago

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saul85 [17]

Answer:

Third option.

Step-by-step explanation:

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$(a^m)^n=a^{mn$

$\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d})\\\\(\sqrt[3]{162x^cy^5})^3=(3x^2y(\sqrt[3]{6y^d}))^3\\\\162x^cy^5=27x^6y^36y^d$

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