Answer:
x = 12z + 1 and y = 10z - 1
Step-by-step explanation:
To solve the system of equations, we can use the substitution method
If we call
3x - 4y + 4z = 7 I
x - y - 2z = 2 II
2x - 3y + 6z = 5 III
Clearing II x = 2 + y + 2z
Now, replacing II in III
2(2 + y + 2z) - 3y +6z = 5
4 + 2y + 4z - 3y + 6z = 5
10z - y = 1 from here y = 10z - 1
Finally, replacing y in I
3x - 4(10z - 1) + 4z = 7
3x -40z + 4 + 4z = 7
3x - 36z = 3
3x = 36z + 3
x = 12z + 1
Done
Answer:
the 3rd one
Step-by-step explanation:
Hope it helped :) please mark brainliest :)
Answer:
For a third degree polynomial, we need 3 linear factors.
Since
5
and
2
i
are roots (zeros), we know that
x
−
5
and
x
−
2
i
are factors.
If we want a polynomial with real coeficients, then the complex conjugate of
2
i
(which is
−
2
i
) must also be a root and
x
+
2
i
must be a factor.
One polynomial with real coefficients that meets the requirements is
(
x
−
5
)
(
x
−
2
i
)
(
x
+
2
i
)
=
(
x
−
5
)
(
x
2
+
4
)
=
x
3
−
5
x
2
+
4
x
−
20
Any constant multiple of this also meets the requirements.
For example
7
(
x
3
−
5
x
2
+
4
x
−
20
)
=
7
x
3
−
35
x
2
+
28
x
−
140
Simplify both sides of the equation and then isolate the variable
x=8
Answer:
2 8/9
Step-by-step explanation:
B3cause when you subtract 5 4/9 and 2/59 you get 2 /89