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Gala2k [10]
3 years ago
8

Select all of the expressions that are equal to 6.

Mathematics
1 answer:
AfilCa [17]3 years ago
3 0
A,d.e are the correct answers that equal 6
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Is this a right triangle yes or no ?​
slega [8]

Answer:

I don't think so, regular triangle sizes are 3, 4,5. If I am wrong please tell me.

Step-by-step explanation:

3 0
2 years ago
A food can claim it is "high in" a particular nutrient if it contains 20% or more of the DV. This food is a "high ____" food.
oee [108]

Answer: Iron

Explanation:

The food contain high iron food as the daily value (DV) of the iron is 45% and most of the nutrient claimed that food contain low sodium but contain good source of the fiber. The food is high in the amount of the nutrient with 20% daily value.

The daily value actually recommend the minimum amount of the particular nutrient which everyone should consume in daily life.

 

3 0
3 years ago
A local university wanted to understand what students prefer to eat during finals. They asked 1000 students, "Do you prefer chic
olga55 [171]

Answer:

P(\text{Pizza}\ |\ \text{Female})=0.225

Step-by-step explanation:

The two-way frequency table is attached below.

We have to calculate the probability of, a person chosen at random prefers pizza given that they are female, i.e P(\text{Pizza}\ |\ \text{female})

This is a conditional probability.

We know that,

P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}

So,

P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}

From the table,

P(\text{Pizza}\ \cap\ \text{Female)}=\dfrac{119}{1000}

P({\text{Female}})=\dfrac{530}{1000}

Putting the values,

P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}=\dfrac{\frac{119}{1000}}{\frac{530}{1000}}=0.225

8 0
3 years ago
In order to determine whether or not a variable type of process is in control (whereoutput can be measured, not just classified
Tema [17]

Answer:

i dont know

Step-by-step explanation:

just working

6 0
3 years ago
Simplify the expression (-2 -c) (-1)
liq [111]
(-1)(-2-c)

multiply -1 to both -2 & -c

-1 x -2 = 2
-1 x -c = c


2 + c is your answer

hope this helps
5 0
3 years ago
Read 2 more answers
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