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Alla [95]
3 years ago
13

I'm stuck, can any one help me please?

Mathematics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

4 times 2+3-1=10

Step-by-step explanation:

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Please helpp!!!!
fomenos

Answer:

Dom(gof)=Dom(f)={1,3,4}.

(gof)(1)=g{f(1)}=g(2)=3.

(gof)(3)=g{f(3)}=g(5)=1.

(gof)(4)=g{f(4)}=g(1)=3.

∴gof={(1,3),(3,1),(4,3)}.

7 0
3 years ago
Timed! Does anyone know this algebra question? Will give brainiest
sineoko [7]

square root of 3 is the correct answer, the first choicw

5 0
3 years ago
Rename 5/6 and 14/15 using the least common denominator.
baherus [9]

Answer:

\frac{25}{30}~and~\frac{28}{30}

  • Multiply 5 by 5 to get your first parameter.

5 * 5 = 25

  • Multiply 6 by 5 to get the denominator, or your second parameter.

5 * 6 = 30

  • For the second fraction, \frac{14}{15}, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.

14 * 2 = 28

  • Now, multiply 15 by 2

15 * 2 = 30

  • The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.

25~and~30 -- > \frac{25}{30}

28~and~30-- > \frac{28}{30}

________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

________________________________________________________

<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

8 0
3 years ago
A triangle can be formed with side lengths 2in, 3in and 6 in?<br>true or false?​
Aleks04 [339]

Answer:

No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.

For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.

2

in.

+

3

in.

=

5

in.

5

in.

<

6

in.

For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:

3 + 4 = 7 which is greater than 5

3 + 5 = 8 which is greater than 4

4 + 5 = 9 which is greater than 3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Need help on A and B thank you
lesya [120]
A 78 lollll I need points so I’m guessing
7 0
3 years ago
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