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4 years ago

I REALLY NEED HELP WITH THIS QUESTION ILL GIVE 15 FREE POINTS PLUS BRAINLIEST FOR CORRECT ANSWER!!!

Mathematics

2 answers:

OleMash [197]4 years ago

7 0

Nice offer.

For the other guy ( I am here to give other guy brainliest)

Damm [24]4 years ago

3 0

Answer:

C. Irrational because it is a non-terminating and non repeating

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Line K has the equation y=5x-4.

Marat540 [252]

<h3>Answer: y = 5x+3</h3>

Explanation:

Parallel lines always have equal slopes, but different y intercepts.

Line K has a slope of 5, which means line L also has this slope too. Refer to the y = mx+b form.

Plug in the coordinates of (-2,-7) as well as the slope mentioned and solve for b.

y = mx+b

-7 = 5(-2) + b

-7 = -10+b

-7+10 = b

3 = b

b = 3

The y = mx+b updates to the final answer of y = 5x+3

5 0

2 years ago

13) -3x - 4y = 8<br>-4x - 3y=6

Dvinal [7]

Answer:

x = 0, y = -2

Step-by-step explanation:

-3x - 4y = 8 (1)

-4x - 3y=6 (2)

Multiply (1) by -4 and (2) by -3, we have:

12x + 16y = - 32 (3)

12x + 9y= -18 (4)

Subtract (4) from (3), we have:

(12x + 16y) - (12x + 9y) = - 32 - (-18)

<=> 7y = - 14

=> y = - 2

Replace y with - 2 in (3), we have x = 0

6 0

4 years ago

HELP PLEASE !!!!!!!!!!!!!!!

valina [46]

(f×g)(x) = (fg)(x)

(f×g)=(3x²+5)× (x-2)

use the foil method:

(fg)(x)=3x³-6x²+5x-10

so it is C which is correct

4 0

3 years ago

Suppose a set of test scores is appproximately bell-shaped, with a mean of 68 and a range of 54. (a) The minimum test score is a

liberstina [14]

Answer:

a.) Minimum test score = 41

Maximum test score = 95

b.)An approximate value of the standard deviation is 9.

Step-by-step explanation:

The given set of test scores is approximately bell shaped.

The mean of the test scores, $\mu$ = 68

The range of the data set = 54.

a.) i.) Minimum test score = $\mu - \frac{range}{2} = 68 - \frac{54}{2} = 68 - 27 = 41$

ii.) The maximum test score = $\mu + \frac{range}{2} = 68 + \frac{54}{2} = 68 + 27 = 95$

b.) From the 68-95-99.7 rule, also known as the Empirical rule, tell us that an approximation of the range is 3 standard deviations either way from the mean. So from this rule we can say that the minimum can also be found from $\mu - 3\sigma$ and the maximum can also be approximated as $\mu + 3\sigma$ .