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4 years ago

11

I REALLY NEED HELP WITH THIS QUESTION ILL GIVE 15 FREE POINTS PLUS BRAINLIEST FOR CORRECT ANSWER!!!

2 answers:

OleMash [197]4 years ago

7 0

Nice offer.

For the other guy ( I am here to give other guy brainliest)

Damm [24]4 years ago

3 0

Answer:

C. Irrational because it is a non-terminating and non repeating

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<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%

SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

3 years ago

X/3=-19<br> What is the value of x

Molodets [167]

<h3>I'll teach you how solve X/3=-19</h3>

-----------------------------------------------

X/3=-19

Multiply both sides by 3:

3x/3= 3(-19)

Simplify:

x= -57

Your Answer Is x= -57

plz mark me as brainliest :)

8 0

3 years ago

Read 2 more answers

Someone Help me please??

11Alexandr11 [23.1K]

It will be identical, this will explain it https://www.wyzant.com/resources/answers/165599/how_many_degrees_can_a_regular_pentagon_be_rotated_a...

8 0

4 years ago

Read 2 more answers

Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a

EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, $\sin x$ and $\cos x$ are defined for all real numbers.

$\tan x=\frac{\sin x}{\cos (x)}$ , this function is not defined where $\cos x=0$ .

$\cot x=\frac{\cos x}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

$\csc x=\frac{1}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

For option A

The domain of $f(x)=\sin(x)$ is all real numbers.

The domain of g(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

For option B

The domain of $f(x)=\cos(x)$ is all real numbers.

The domain of f(x) =csc(x) is $x\ne n\pi$

For option C,

The domain of G(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

The domain of f(x) =cot(x) is $x\ne n\pi$

For option D;

The domain of f(x) =cot(x) is $x\ne n\pi$

The domain of f(x) =csc(x) is $x\ne n\pi$

3 0

4 years ago

Read 2 more answers

For questions 1 - 8, list all the factors of the following numbers from least to greatest.

IrinaK [193]

Answer:

1. 1, 2, 5, 10

2. 1, 5, 25

3. 1, 2, 4, 8, 16, 32

4. 1, 3, 9, 27, 81

5. 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

6. 1, 2, 4, 5, 10, 20, 25, 50, 100

7. 1, 5, 25, 125

8. 1, 2, 4, 11, 22, 44

Step-by-step explanation:

Hope this helps!

4 0

3 years ago