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True [87]
3 years ago
8

Irina rode her bike to work at an average speed of 16 miles per hour. It started to rain, so she got a ride home along the same

route in her coworker’s car at an average speed of 27 miles per hour. If Irina’s ride home in the car took 24 minutes (0.4 of an hour), how many hours was her bike ride to work, to the nearest tenth of an hour?
Mathematics
1 answer:
Sedaia [141]3 years ago
3 0

Answer:

0.7 hours

Step-by-step explanation:

Given that Irina was able to make the same distance from work to home in 0.4 of an hour at 27 miles per hour, we can use this rate and time to find the distance she travels to and from work using the general formula:

d = rt, where d=distance, r = rate and t = time

d = 27(0.4) = 10.8 miles

Since the distance from Irina's home to work is 10.8 miles, we can again use the formula 'd = rt' to find the time it takes her to bike to work at a rate of 16 miles per hour and solving for time, 't':

10.8 = (16)t

t = 0.7 hours

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Answer:

30 units.  

Step-by-step explanation:

Let x be number of milk units sold.

It has been given that You begin the week with 20 units of milk. You purchase 40 units. Therefore, total units of milk will be 20+40=60 units.

It has been given that your ending inventory for the week is 30 units, which means after selling x units from 60 units you are left with 30 units.

We can set this information in an equation as:

60-x=30

-x=30-60

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x=30

Therefore, you have sold 30 units.

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3 years ago
The greatest common factor of any two even numbers is always even. determine weather the statement is true or false. if true exp
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True. Because two even numbers weather you Add Subtract or Multiply them they will always be Even
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3 years ago
PLEASE HELP! I HAVE TWO QUESTIONS AND WILL GIVE 100PTS AND BRAINLIEST IF CORRECT!
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Answer:

1) $283.50

2) 65.21 meters.

Step-by-step explanation:

Part 1)

We know that a spool of ribbon holds 6.75 meters.

A craft club buys 21 spools.

So, the total length of ribbon bought is:

T=21(6.75)=141.75\text{ meters}

Each meter costs $2. So, the total cost will be:

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Part 2)

A spool holds 6.75 meters.

We bought 21 of them, so that total length we have is 141.75 meters.

The club used 76.54 meters.

So, the amount of ribbon that is left is represented by:

141.75-76.54

Subtract:

=65.21\text{ meters}

So, 65.21 meters of ribbon will be left.

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The function A=A_oe^{-0.01155x} A = A o e − 0.01155 x models the amount in pounds of a particular radioactive material stored in
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They are essentially asking us to solve:

357=900e^{-0.01155x} \implies\\ \frac{357}{900}=e^{-0.01155x} \implies\\ \ln{\frac{357}{900}}=-0.01155x \implies \\ x\approx 80.1

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3 years ago
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