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2 years ago

How many units are in a milli

Mathematics

1 answer:

Arlecino [84]2 years ago

8 0

Answer:

1,000

Step-by-step explanation:

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The battery standby duration (in hours) of a new model of cell phone is known to be normally distributed. Ten pieces of such new

Stells [14]

x = number of hours

want to find probability (P) x >= 13

x is N(14,1) transform to N(0,1) using z = (x - mean) / standard deviation so can look up probability using standard normal probability table.

P(x >= 13) = P( z > (13 - 14)/1) = P(z > -1) = 1 - P(z < -1) = 1 - 0.1587 = 0.8413

To convert that to percentage, multiply 100, to get 84.13%

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2 years ago

If < A and < B are vertical angles, and < A = 2x - 11 degrees, and < B = x + 7 degrees, find x.

Tema [17]

Answer:

x=18

Step-by-step explanation:

Vertical angles are congruent. This means that they are equal to each other. So, to solve set them equal to each other and isolate x. First, set up the equation. Then, subtract x from both sides. Finally, add 11 to both sides and simplify.

1) $2x-11=x+7$

2) $x-11=7$

3) $x=18$

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3 years ago

Someone pls help im so close

Sliva [168]

Answer: A) 126.6

<u>Step-by-step explanation:</u>

Since we know ∠B = 85° and ∠C = 53°, we can use the Triangle Sum Theorem (angles of a triangle = 180°) to calculate ∠A.

∠A + ∠B + ∠C = 180

∠A + 85 + 53 = 180

∠A + 138 = 180

∠A = 42

Now we have:

A = 42 B = 85 C = 53

a = 85 b = ??? c = ???

We have all of the information for ∠A and side a so we can use the Law of Sines to find b (AC).

$\dfrac{\sin 42}{85}=\dfrac{\sin 85}{b}\\\\\\b(\sin 42)=85(\sin 85)\\\\\\b=\dfrac{85\sin 85}{\sin 42}\\\\\\b=\large\boxed{126.547}$

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3 years ago

Given that 1 inch = 2.54 cm, how many centimeters are there in 7 feet?

Zanzabum

The answer is 216.72 cm

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2 years ago

Read 2 more answers

If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

5 0

3 years ago