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GaryK [48]
3 years ago
13

F(1,2)=(3,5) , f(0,2)=(4,-6) tìm ma trận của f đối với cơ sở của R^2 lả B={u=(1,1), v=(3,1)}

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

yeet

Step-by-step explanation:

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Can anyone help? PLS I NEED THIS BY TOMORROW!!
Sveta_85 [38]

Answer:5 or 5 degrees

Step-by-step explanation:

the box means 90 degree so if you divide 45 with 90 you get 2

2 divided by 10 = 5

4 0
3 years ago
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By rounding to 1 significant figure, estimate the value of 48.7 x 61.2<br> 11.3
11111nata11111 [884]

Answer : 263

Rounded (1 s.f ) = 300

7 0
3 years ago
A boat propeller spins 1044 times in 3 MINUTES. Find the rate in revolutions per SECOND.
rodikova [14]

Answer:

The answer is 5.8 times a second

Step-by-step explanation:

Divide 1044 by 180 (The number of seconds in 3 minutes)

8 0
3 years ago
Given that (-3,7) is on the graph of f(x), find the corresponding point for the function f(x + 5).
Stella [2.4K]
We have that
<span>(-3,7) is on the graph of f(x), find the corresponding point for the function
f(x + 5)

we know that
in the transformation f(x)-------> f(x+5)
the point (x.y) in f(x) becomes a point (x-5,y) in f(x+5)
so
(-3,7)-----------> becomes a point (-3-5,7)------> (-8,7)

the answer is
</span>(-8,7)<span>

</span>
7 0
3 years ago
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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
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