Check the picture below
if their areas are equal then A =A or
(3w)(w-2) = (w+1)(w)
solve for "w"
if their areas are equal then A =A or
(3w)(w-2) = (w+1)(w)
solve for "w"
F(1,2)=(3,5) , f(0,2)=(4,-6) tìm ma trận của f đối với cơ sở của R^2 lả B={u=(1,1), v=(3,1)}
1 answer:
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we have the inequality
step 1
Find out the first solution (positive case)
The first solution is all real numbers less than or equal to 1.20
Interval (-infinite,1.20]
step 2
Find out the second solution (negative case)
Multiply by -1 both sides
The second solution is all real numbers greater than or equal to -2.8
the interval [-2.8, infinite)
step 3
Find out the solution to the given inequality
The solution is
[-2.8, infinite) ∩ (-infinite,1.20]=[-2.8,1.20]
the solution is the interval [-2.8,1.20]
see the attached figure to better understand the problem
Answer:
<h2>√34sin(x + 0.33π)</h2>Step-by-step explanation:
The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.
R = √a²+b²
Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;
a = 3, b = 5
R = √3²+5²
R = √9+25
R =√34
in radians;
3 cos x + 5 sin x = √34sin(x + 0.33π)