Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :
C is constant. Here the ball is launched from a height of 6 feet. So,
At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Answer:
12
Step-by-step explanation:
Simplifying
18x + -6y = 12
Solving
18x + -6y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '6y' to each side of the equation.
18x + -6y + 6y = 12 + 6y
Combine like terms: -6y + 6y = 0
18x + 0 = 12 + 6y
18x = 12 + 6y
Divide each side by '18'.
x = 0.6666666667 + 0.3333333333y
Simplifying
x = 0.6666666667 + 0.3333333333y
Answer:
nearby -3
Step-by-step explanation:
When v^3 is -26, your v is equal to ![-\sqrt[3]{26}](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7B26%7D)
.
3^3 is 27, so v is nearby 3.
or, It would be nearby 3.9
