Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
The answer to this is the third option choice: Reaches a maximum height of 549 after 5.75 seconds.
Answer:
(x+3)(x+2)
Step-by-step explanation:
I can't explain it well, but I call it "reverse foil."
Answer: Second option is correct.
Step-by-step explanation:
Since we have two spinners,
Each spinner has 10 equal sectors labeled with the numbers from 1 to 10.
Primes numbers from 1 to 10 is given by
So, number of outcomes shows a primes number from 1 to 10 = 4
Similarly ,
Composite numbers from 1 to 10 is given by
So, number of outcomes shows a composite number from 1 to 10 =5
∴ Total outcomes show a prime number on the first spinner and a composite number on the second spinner is given by
Thus, Second option is correct.
