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yulyashka [42]
3 years ago
11

The table below shows the number of miles that a cross country team ran each day last week. What is the mean number of miles? Ro

und your answer to the nearest tenth, if necessary. Cross Country Training Routine Day Miles Mon 6 Tues 8 Wed 7 Thurs 6 Fri 8 Sat 7 Sun 8 Group of answer choices 7.1 miles 6.7 miles 6.3 miles None of the other answers are correct 7 miles
Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer:

7 miles.

Step-by-step explanation:

6+8+7+6+7+8/6

42/6

= 7 miles

The answer is 7 miles.

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At dan's school,6 out of every 10 kids know how to swim. If there are 350 kids in his school,how many know how to swim?
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BRIANILEST!!!!Which lines are parallel? Check all that apply.
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Answer:

b║f

c║e

Step-by-step explanation:

Given a diagram,

Lines b, c, d, e, f and a transversal line 'a'.

Here line 'b' makes an angle with line 'a' is 89.5° and line 'f' makes an angle with line 'a' is also 89.5° (180°-90.5° = 89.5°)

Since corresponding angles are same.

So, line 'b' is parallel to line 'f'.

And line 'c' makes an angle with line 'a' is 91.5° and line 'e' makes an angle with line 'a' is also 91.5° (180°-88.5° = 91.5°)

Since corresponding angles are same.

So, line 'c' is parallel to line 'e'.

Therefore,

b║f

c║e

That's the final answer.

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\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

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3 years ago
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