The answer is 2x+1..... i Recommend you downloading the app called Photomath… It really helps for problems like these and any problem really.
Answer:
I believe (D)
Step-by-step explanation:
-5x + 7 = -13
-7 -7
-5x = -20
-5/-5 -20÷-5
x=4
The answer to this question is 12y.
Step-by-step explanation:
Consider an engineering material of initial length Lo, Area (A), Modulus of elasticity (E) and applied a force P due to which change in the length of the material is δ2 from it’s original length (Lo)
Initial length of the material is Lo. Hence, at time t = 0 when no force applied on the material the length of the material will not change (i.e., at time t=0, δ1 = 0)
Modulus of elasticity of the material:
![E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BP%20%5Ccdot%20L_%7Bo%7D%7D%7BA%5Cleft%5B%5Cdelta_%7B2%7D-%5Cdelta_%7B1%7D%5Cright%5D%7D)
Area of the material:
![E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BP%20%5Ccdot%20L_%7Bo%7D%7D%7BA%5Cleft%5B%5Cdelta_%7B2%7D-%5Cdelta_%7B1%7D%5Cright%5D%7D)
![A=\frac{P \cdot L_{o}}{E\left[\delta_{2}-\delta_{1}\right]}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7BP%20%5Ccdot%20L_%7Bo%7D%7D%7BE%5Cleft%5B%5Cdelta_%7B2%7D-%5Cdelta_%7B1%7D%5Cright%5D%7D)
Length of the material:
![E=\frac{P \cdot L_{0}}{A\left[\delta_{2}-\delta_{1}\right]}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BP%20%5Ccdot%20L_%7B0%7D%7D%7BA%5Cleft%5B%5Cdelta_%7B2%7D-%5Cdelta_%7B1%7D%5Cright%5D%7D)
![L_{0}=\frac{E \cdot A\left[\delta_{2}-\delta_{1}\right]}{P}](https://tex.z-dn.net/?f=L_%7B0%7D%3D%5Cfrac%7BE%20%5Ccdot%20A%5Cleft%5B%5Cdelta_%7B2%7D-%5Cdelta_%7B1%7D%5Cright%5D%7D%7BP%7D)
15 square units. Its right