Question

In engineering, the modulus of elasticity is a way to measure how much an object deforms along an axis when opposing forces are applied among that axis. The formula can be expressed as E=(F2−F1)L0(δ2−δ1)A , where E is the modulus of elasticity, F is the axial force, δ is a deformation measure, L0 is the original length of the object, and A is the cross-sectional area.

Answer 1

Step-by-step explanation:

Consider an engineering material of initial length Lo, Area (A), Modulus of elasticity (E) and applied a force P due to which change in the length of the material is δ2 from it’s original length (Lo)

Initial length of the material is Lo. Hence, at time t = 0 when no force applied on the material the length of the material will not change (i.e., at time t=0, δ1 = 0)

Modulus of elasticity of the material:

$E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}$

Area of the material:

$E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}$

$A=\frac{P \cdot L_{o}}{E\left[\delta_{2}-\delta_{1}\right]}$

Length of the material:

$E=\frac{P \cdot L_{0}}{A\left[\delta_{2}-\delta_{1}\right]}$

$L_{0}=\frac{E \cdot A\left[\delta_{2}-\delta_{1}\right]}{P}$