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3 years ago

10

What is the answer?

2 answers:

noname [10]3 years ago

7 0

B. y = -8(4^x) because the negative will make it reflect

slega [8]3 years ago

4 0

Answer:

its B because the line is on -8 and if we do rise over run we go up four and turn once.

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There's got to be someone who can answer this

Sphinxa [80]

Yes based on ja 82 and it can be added

4 0

3 years ago

27-28 . Find the acute angles between the curves at their points of intersection. (The angle between two curves is the angle bet

aleksandrvk [35]

Answer:

27.The angle between two given curves is $0^{\circ}$ .

28. $\theta=tan^{-1}(2\sqrt2)$

Step-by-step explanation:

27.We are given that two curves

y=x,y=x

We have to find the angle between the two curves

The angle between two curves is the angle between their tangent lines at the point of intersection

We know that the values of both curves at the point of intersection are equal

Let two given curves intersect at point $(x_1,y_1)$

Then $y_1=x_1$ because both curves are same

$\frac{dy}{dx}=1$

$m_1=1,m_2=1$

$m_1(x_1)=1,m_2(x_1)=1$

Using formula of angle between two curves

$tan\theta=\frac{m_1(x_0)-m_2(x_0)}{1+m_1(x_0)m_2(x_0)}$

$tan\theta=\frac{1-1}{1+1}=\frac{0}{2}=0$

$tan\theta=tan 0^{\circ}$

$\theta=0^{\circ}$

Hence,the angle between two given curves is $0^{\circ}$ .

28.y=sin x

y= cos x

By similar method we solve these two curves

Let two given curves intersect at point (x,y) then the values of both curves at the point are equal

Therefore, sin x = cos x

$\frac{sin x}{cos x}=1$

$tan x=1$

$tan x=\frac{sin x}{cos x}$

$tan x= tan \frac{\pi}{4}$

$x=\frac{\pi}{4}$

Now, substitute the value of x then we get y

$y= sin \frac{\pi}{4}=\frac{1}{\sqrt2}$

$sin \frac{\pi}{4}=cos \frac{\pi}{4}=\frac{1}{\sqrt2}$

The values of both curves are same therefore, the point $(\frac{\pi}{4},\frac{1}{\sqrt2})$ is the intersection point of two curves .

$m_1=cos x$

At $x=\frac{\pi}{4}$

$m_1=\frac{1}{\sqrt2}$

and

$m_2=-sin x=-\frac{1}{\sqrt2}$

Substitute the values in the above given formula

Then we get $tan\theta =\frac{\frac{1}{\sqrt2}+\frac{1}{\sqrt2}}{1-\frac{1}{2}}$

$tan\theta=\frac{\frac{2}{\sqrt 2}}{\frac{1}{2}}$

$tan\theta=\frac{2}{\sqrt 2}\times 2$

$tan\theta=\frac{4}{\sqrt2}=\frac{4}{\sqrt 2}\times\frac{\sqrt2}{\sqrt2}$

$tan\theta=2\sqrt2$

$\theta=tan^{-1}(2\sqrt2)$

Hence, the angle between two curves is $tan^{-1}(2\sqrt2)$ .

4 0

3 years ago

Write an equation for the line parallel to the x-axis through the point (0,9)

solong [7]

The answer is Y equals 9 because the line is parallel making the slope 0

8 0

4 years ago

Help now plz will give 98 points and mark brainliest plz help

goblinko [34]

X = 7 here’s a picture on how you do it

7 0

3 years ago

Read 2 more answers

What is the answer to this along with steps to doing it?

pashok25 [27]

1/2*(2*8)=3*(-12)
1/2*16=3*(-12)
1/2*16= -36
8= -36
The equality is false because the left hand and right hand side are different

8 0

3 years ago