1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
drek231 [11]
3 years ago
10

PLLLLLEEEAAAAASSSSEEE ANSWER NEED HELP!!!!!!!!!!!!!!!!!!!!!! WILL MARK 5 STARS!!!!!!!!!!!!!!!!

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

UT = 8

Step-by-step explanation:

From the picture, we can make the following equation...

5 + 2x - 6 = x + 6

By solving it we get

5 + 2x - 6 = x + 6

2x - 1 = x + 6

2x = x + 7

x = 7

Therefor if UT = 2x - 6, then UT is equal to...

2x - 6 = UT

2(7) - 6 = UT

14 - 6 = UT

8 = UT

You might be interested in
First in your notebook, draw a right angle, then draw a bisector of the right angle. Label all parts. Looking at the right angle
crimeas [40]
Two acute angles are formed by the bisector, 45 degrees each.
6 0
3 years ago
Read 2 more answers
Write an equation if the line that is parallel to y=2x-5 and passes through (-4,2)
Leokris [45]

Answer:

Step-by-step explanation:

y=2x-5

From y=mx+c

Comparing the equation

M=2.

For parallelism

M₁=M₂

y-y₁=m(x-x₁) equation of a line passing through a point

point (-4,2) are x₁ and y₁ respectively

y-2=2(x-(-4))

y-2=2(x+4)

y-2=2x+8

y=2x+8+2

y=2x+10

5 0
4 years ago
40 POINTS FOR THIS ALGEBRA WORD PROBLEM
skelet666 [1.2K]

Answer:

9

Step-by-step explanation:

let the number

=

x

then 4 times the number

=

4

x

and 4 times the number increased by 15

=

4

x

+

15

also 6 times the number

=

6

x

and 3 less than 6 times the number

=

6

x

−

3

equating the two expressions gives the equation

4

x

+

15

=

6

x

−

3

←

solve for x

subtract 6x from both sides

4

x

−

6

x

+

15

=

6

x

−

6

x

−

3

⇒

−

2

x

+

15

=

−

3

subtract 15 from both sides

−

2

x

+

15

−

15

=

−

3

−

15

⇒

−

2

x

=

−

18

divide both sides by

−

2

−

2

x

−

2

=

−

18

−

2

⇒

x

=

9

As a check

(

4

×

9

)

+

15

=

36

+

15

=

51

(

6

×

9

)

−

3

=

54

−

3

=

51

⇒

the number is 9

7 0
3 years ago
Read 2 more answers
I got b = 5 but I wanted to make sure from you beautiful ppl <3
GrogVix [38]

Answer:

b=5

Step-by-step explanation:

10 = -2b + 4b

Combine like terms

10 = 2b

Divide each side by 2

10/2 = 2b/2

5 = b

4 0
3 years ago
Read 2 more answers
What's the inequality for |u|-2<5
Andrew [12]

Answer:

0 ≤ u < 7 and 0 > u > - 7 and combining those two we get - 7 < u < 7.

Step-by-step explanation:

The given inequality is |u| - 2 < 5 ....... (1)

We have to solve this inequality.

Now, from the definition of f(x) = |x| we get, f(x) = x, when x ≥ 0 and  

f(x) = -x when x < 0.

Hence, for u ≥ 0, the equation of inequality (1) becomes  

u - 2 < 5

⇒ u < 7

Therefore, the solution is 0 ≤ u < 7 (Answer)

Again, for u < 0, the equation of inequality (1) becomes

- u - 2 < 5

⇒ u + 2 > - 5

⇒ u > - 7

Therefore, the solution becomes 0 > u > - 7 (Answer)

6 0
4 years ago
Other questions:
  • Find the midpoint of the line segment with the given endpoints (6,6) and (-9,2)
    13·2 answers
  • Write an equation in​ point-slope form of the line that passes through the given​ points, then write the equation in​ slope-inte
    5·1 answer
  • What is 2,520 divided by 16?
    5·2 answers
  • Which equation is the inverse of y = 100 – x2?
    8·1 answer
  • Solve for the variable
    14·2 answers
  • Please help me with the answer u am behind a lot of work trying to avoid 0
    11·1 answer
  • 2(x-4)=6x+4 solve plz
    8·2 answers
  • Which table contains only values that satisfy the equation y = -x +7?
    9·1 answer
  • What is the answer to this radical equation<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%20%2B%2013%3D7%7D" id="TexFormula1
    8·2 answers
  • Please help me. I really need help. and I'm not smart
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!