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Lostsunrise [7]
3 years ago
9

Shauna spent $175 on a pair of shoes.She spent 1/9 of the remaining money on a shirt.If he still had 4/7of his moneyleft,how muc

h did he have at first
Mathematics
1 answer:
KIM [24]3 years ago
3 0

Answer:

$490

Step-by-step explanation:

Shauna spent $175 on a pair of shoes.

She spent 1/9 of the remaining money on a shirt.

If he still had 4/7 of his money left,how much did he have at first ?

Solution:

Let at first, Shauna have = x

Money spent on a pair of shoes = $175

Remaining money = x-175

<u>As she spent 1/9 of the remaining money on a shirt.</u>

Money spent on shirt = \frac{1}{9} \times(x-175)=\frac{x}{9} -\frac{175}{9}

As he still had \frac{4}{7} of his money left:-

Money left = \frac{4}{7}\ of\ his\ money=\frac{4x}{7}

Money left with Shauna = Total money, she had at first -(Money spent on a pair of shoes + Money spent on shirt )

\frac{4x}{7} =x-(175+{\frac{x}{9} -\frac{175}{9} )\\\\\\

\frac{4x}{7} =x-(\frac{175}{1} -\frac{175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7} =x-(\frac{1575-175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7}=x-(\frac{1400}{9} +\frac{x}{9} )\\ \\ \frac{4x}{7}=x-\frac{1400}{9} -\frac{x}{9}

Subtracting both sides by x and adding both sides by \frac{x}{9}

\frac{4x}{7} -x+\frac{x}{9} =-\frac{1400}{9} -x+\frac{x}{9} +x-\frac{x}{9}

Taking LCM of 7 and 9, we get 63

\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ -\frac{20x}{63}=-\frac{1400}{9}

Adding both side by -

\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ \frac{20x}{63}=\frac{1400}{9}

By cross multiplication:

20x\times9=1400\times63\\180x=88200\\

Dividing both sides by 180

x=490

Therefore, total $490, she had at first.

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