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Ipatiy [6.2K]
3 years ago
5

Which three lengths could be the lengths of the sides of a triangle? A.21 cm, 7 cm, 7 cm B.9 cm, 14 cm, 22 cm C.15 cm, 5 cm, 20

cm D.20 cm, 6 cm, 8 cm
Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0
B.) 9 cm, 14 cm, 22 cm

It would make an obtuse triangle, and by using the triangle calculator trick or ways you would have to find the area of the triangle, but it would get to confusing...

But also the simplest way or elementary would be

A.) 21 cm, 7 cm 7 cm

I messed up my self I'm am truly sorry but,

I hoped this helped!! <33
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Answer:

20 + 2x = 4x

Step-by-step explanation:

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buying a membership card  and paying each time looks like this: 20 + 2x where x is the number of times you go to the gym.  20 dollars base then 2 each time you go.

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3 years ago
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Answer:

35

Step-by-step explanation:

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3 years ago
Integrate e^x(sin(x) cos(x))
Karo-lina-s [1.5K]
I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx

\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\&#10;\text{Using }\int u\,dv=uv-\int v\,du:\\\\&#10;I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\&#10;2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}

Looking for I_2:

\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\&#10;I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\  I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I

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2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\&#10;2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\&#10;10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\&#10;I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\&#10;\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}
6 0
3 years ago
What is 5+2 x 34-19+85-23​
liubo4ka [24]

Answer:

=2x34+48

Step-by-step explanation:

Let's simplify step-by-step.

5+2x34−19+85−23

=5+2x34+−19+85+−23

Combine Like Terms:

=5+2x34+−19+85+−23

=(2x34)+(5+−19+85+−23)

=2x34+48

Answer:

=2x34+48

8 0
2 years ago
Read 2 more answers
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