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Sidana [21]
3 years ago
13

Which of the following statements is true?

Chemistry
2 answers:
german3 years ago
8 0

Answer:  Solids have a fixed mass, volume, and shape.

Explanation:  Solids are the substances which have fixed shape, fixed volume and mass due to its close packed structure.

Dalton explained that all the elements are made up of small indivisible particle known as Atoms but after some time this was proved wrong as atoms is not indivisble, it conatins sub atomic particle like electrons, protons, neutrons etc.

Plasmas are considered as the fourth state of matter which contains equal quantity of positive ions and negative electrons.

The number of protons are equal to the number of electrons. The sum of number of protons and neutrons make the atomic mass quantity.

Alexandra [31]3 years ago
4 0
Solids have a mixed mass, volume, and shape.
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Compared to a calcium atom, the calcium ion Ca2+ has
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The answer is definitely 4. It has fewer electrons. This is because, whenever the electrons are few, they are positive. Positive electrons are anions, while the negative ones are cations. Hope i helped. Have a nice day.
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A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, c
natka813 [3]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

  • Ca: 40.078.

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

  • The mass of one mole of CaCO₃ is the same as the molar mass of this compound: \rm 100\; g.
  • The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: \rm 40.078\; g.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}.

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be \rm 30 \% \times 100\; g = 30\; g of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio \displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}:

\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}.

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%.

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Answer: the answer is that stop using brainly for your answer dumb kid

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How does the arrangement of particles in a gas differ from the arrangements in liquids and solids?
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The arrangement of particles in a gas is random. they have no orderly arrangement and are free to move around while the particles in solid are in an orderly and rigid arrangement and cannot move about. particles in liquid are also arranged orderly but are not rigid
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