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yuradex [85]
3 years ago
13

¿Como pasar 254 meses a minutos? Por favor ayudaaa!! Le doy corona a la respuesta

Chemistry
1 answer:
Dimas [21]3 years ago
7 0

Answer:

Ver las respuestas abajo.

Explanation:

Este problema se puede resolver conociendo la relacion entre horas y minutos, sabemos que:

1 hora [h] → 60 minutos [min]

De esta manera:

2 [min] = 2/60 = 0.033 [h]

15 [min] = 15/60 = 0.25 [h]

30 [min] = 30/60 = 0.5 [h]

10 [min] = 10/60 = 0.166 [h]

6 [min] = 6/60 = 0.1 [h]

20 [min] = 20/60 = 0.33 [h]

5 [min] = 5/60 = 0.0833 [h]

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Automotive airbags inflate when a sample of sodium azide, NaN3, is very rapidly decomposed.
Kobotan [32]

Answer:

148 g

Explanation:

Step 1: Write the balanced equation for the decomposition of sodium azide

2 NaN₃ ⇒ 2 Na + 3 N₂

Step 2: Calculate the moles corresponding to 95.8 g of N₂

The molar mass of N₂ is 28.01 g/mol.

95.8 g × 1 mol/28.01 g = 3.42 mol

Step 3: Calculate the moles of NaN₃ needed to form 3.42 moles of N₂

The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.42 mol = 2.28 mol.

Step 4: Calculate the mass corresponding to 2.28 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.28 mol × 65.01 g/mol = 148 g

8 0
2 years ago
The force of attraction between a divalent cation and a divalent anion is 1.64 x 10-8 N. If the ionic radius of the cation is 0.
Elden [556K]

The radius of the anion is 7.413 nm

<h3>How to calculate the force of attraction between charges</h3>

The force of attraction (F) is given by the formula:

  • F = (1/4π∈r²)(Zc*e)(Za*e)

where:

∈ = permittivity of free space = 8.85*10⁻¹⁵ F/m

Zc = charge on the cation = +2

Zc = charge on the anion = -2

e = charge on an electron = 1.602 * 10⁻¹⁹ C

r = interionic distance

r = rc + ra

where rc and ra are the radius of the cation and anion respectively

F = 1.64 * 10⁻⁸ N

Therefore based on the equation of force of attraction:

1.64 *10⁻⁸ = [1/4π(8.85*10⁻¹⁵)r²](2 * 1.602*10⁻¹⁹)²

r² = 5.63 * 10⁻¹⁷

r = 7.50 nm

Since r = rc + ra

where rc = 0.087 nm

thus, ra = r - rc = 7.50 - 0.087

ra = 7.413 nm

Therefore, the radius of the anion is 7.413 nm

Learn more about ionic radius at: brainly.com/question/2279609

6 0
2 years ago
What is the first answer ?
QveST [7]

Answer:

d....

Explanation:

yes its d

sorry

7 0
2 years ago
Which of these gives a correct trend in ionization energy​
natita [175]

Answer:

C. I, III , IV

Explanation:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

3 0
3 years ago
Find the mass of 1.59 mol of NH3​
xxMikexx [17]

Answer:

27.03 grams

Explanation:

moles (n) = mass(m)/Molar mass(M)

moles = 1.59

mass = ?

N = 14, H = 1

M(NH3) = 14 + 3(1) = 17

Substitute the values into the equation:

nM = m

∴ m = 1.59 × 17 = 27.03

5 0
3 years ago
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